Feb 20, 2018 · A wooden fossil has a c-14 activity of 6.3 beta particles/min/gram of carbon.calculate the age of the fossil if half life of carbon is 5760 yrs?

39.47days If you start with 260mg and end with 210.6mg, then 49.4mg has decayed in 15 days. For a half life, half of a substance needs to decay. Half of 260mg is 130mg. Therefore, when the …

Jun 20, 2017 · Using the half-angle formula for cosine: cos (theta/2) = +-sqrt ( (1+costheta)/2) Therefore...with theta = arcsin (3/5) cos ( (1/2)arcsin (3/5)) = +-sqrt ( ( (1+cos (arcsin (3/5)))/2) Now, …

Think about the conversion of C-14 to N-14 which is a beta decay process which has a half life of about 5,700 years. If you start with 100 C-14 atoms, after 5,700 years (one half life) you should only have …

Since it is not logical to have half an atom multiple the ratio by 2 2.5/1 xx 2/2 = 5/2 There are five Hydrogen to 2 Carbons This is the empirical formula. ( It may not be the molecular formula)

Explanation: Starting with #sin (x/2)-cosx=0#, use the half angle formula for #sin (x/2)#: #sin (x/2)=sqrt ( (1-cosx)/2)# and rewrite the original equation: #sqrt ( (1-cosx)/2)-cosx=0# Add #cosx# to both sides: …

Time it takes for 50% of the original mass to decay. let's say you have 1 kg of the Plutonium Isotope Pu^239 (in 100% pure form). This has a half-life of 24110 years. This means that, after this span of …

Since each time a half-life passes, the concentration halves, halving 3 times gives #1/8# the initial concentration. So when the concentration becomes #1/8# of what it was, three half-lives passed by:

Topic:half-life decay 2.80moles of a radioactive element was originally present in a given sample of compound.if after 45.6moles of it remain,find the half life of this element?

Dec 5, 2017 · This sum can be expressed in the formula: S = A*[(1+P)^(N+1)-1]/P where A - initial and annual investment P - annual interest N - number of years My first assumption was that the interest …